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0=0.00012x^2-146
We move all terms to the left:
0-(0.00012x^2-146)=0
We add all the numbers together, and all the variables
-(0.00012x^2-146)=0
We get rid of parentheses
-0.00012x^2+146=0
a = -0.00012; b = 0; c = +146;
Δ = b2-4ac
Δ = 02-4·(-0.00012)·146
Δ = 0.07008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.07008}}{2*-0.00012}=\frac{0-\sqrt{0.07008}}{-0.00024} =-\frac{\sqrt{}}{-0.00024} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.07008}}{2*-0.00012}=\frac{0+\sqrt{0.07008}}{-0.00024} =\frac{\sqrt{}}{-0.00024} $
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